0=9x^2+6x+1

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Solution for 0=9x^2+6x+1 equation: 



0=9x^2+6x+1

We move all terms to the left:

0-(9x^2+6x+1)=0

We add all the numbers together, and all the variables

-(9x^2+6x+1)=0

We get rid of parentheses

-9x^2-6x-1=0

a = -9; b = -6; c = -1;
Δ = b2-4ac
Δ = -62-4·(-9)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{6}{-18}=-1/3$

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